Pumpjack: Difference between revisions
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Revision as of 19:18, 14 August 2017
| Pumpjack | 
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 Recipe  | 
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 Total raw  | 
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 Map color  | 
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 Fluid storage volume  | 
 1000  | 
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 Health  | 
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 Stack size  | 
 20  | 
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 20  | 
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 Dimensions  | 
 3×3  | 
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 Energy consumption  | 
 90 kW (electric)  | 
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 Mining time  | 
 0.5  | 
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 Mining speed  | 
 1  | 
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 Mining area  | 
 1 tiles  | 
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 Resource drain  | 
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 Pollution  | 
 10/m  | 
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 Module slots  | 
 2 slots  | 
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 Prototype type  | 
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 Internal name  | 
 pumpjack  | 
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 Required technologies  | 
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 Boosting technologies  | 
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 Produced by  | 
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Pumpjacks extract crude oil from oil fields. Each oil field can be covered by only one pumpjack at a fixed spot. The pumpjack will then output an amount of crude oil per cycle equal to 10 multiplied by the field's yield (e.g. 54 crude oil for 538% yield) per second. Without speed modules one pumpjack cycle takes one second to complete.
Extracting oil lowers the field's yield by 1% per 75 pumpjack cycles to a minimum of 20% of the initial yield or 2 oil unit per second, whichever is larger.
Pumpjacks are limited to a maximum output of 100 crude oil per cycle, achieved by an oil field with more than 999% yield. However, such a high yield is fairly rare.
Pumpjacks output tile location is fixed relative to its orientation.
Pumpjacks cannot be placed on a non-oilfield tile.
Tips
If oil fields are depleted ( to the minimum of 20% ) speed Modules are a good option to raise the pumpjacks output. With two Speed module 3's the output doubles from 1 to 2 crude oil per second and even more when using additional Basic beacons ( + another 0.5 oil per beacon per second ).
The formula to determine the modified output is:
Output of unmodified oil field * ( Number of modules in pumpjack * bonus from module ) + output of unmodified oil field * ( number of Beacons * ( number of modules * distribution efficiency ) * bonus from module + 1 )
| Example | |
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| For 1 pumpjack on a depleted oil field with two lvl 3 speed modules and 6 beacons with each two lvl 3 speed modules: | 0,1 * ( 2 * 0,5 ) + 0,1 * ( 6 * ( 2 * 0,5 ) 0,5 + 1 ) = 0,5 Crude oil per 1 second. | 
| Assuming that there will be always 2 modules equipped in pumpjack and beacons, formula can be shortened : | 0,1 + 0,1 * ( 6 * 0,5 + 1 ) = 0,5 Crude oil per 1 second. | 
History
- 0.15.0: Pumpjacks can be turned on and off using the circuit network. They can also output the current oil mining rate.
 
- 0.9.0: 
- Introduced
 
 
