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Pumpjack: Difference between revisions

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(→‎Tips: Clarified formula. See Discussion)
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The formula to determine the modified output is:
The formula to determine the modified output is:


Output of unmodified oil field * (number of modules in pumpjack * bonus from module) + output of unmodified oil field * (number of beacons * (number of modules * distribution efficiency) * bonus from module + 1).
Output of unmodified oil field * [1 + (number of modules in pumpjack * bonus from module) + (number of beacons * distribution efficiency * (number of modules in each beacon * bonus from module))].


{| class="wikitable"
{| class="wikitable"
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|-
|-
|For 1 pumpjack on a depleted oil field with two level 3 speed modules and 6 beacons with each two level 3 speed modules:
|For 1 pumpjack on a depleted oil field with two level 3 speed modules and 6 beacons with each two level 3 speed modules:
|2 * (2 * 0,5) + 2 * ( 6 * ( 2 * 0,5 ) 0,5 + 1 ) = 10 Crude oil per 1 second.  
|2 * [1 + (2 * 0,5) + (6 * 0,5 * (2 * 0,5)) ] = 10 Crude oil per 1 second.  
|-
|-
|Assuming that there will be always 2 modules equipped in the pumpjack and beacons, the formula can be shortened:
|Assuming that there will be always two speed 3 modules equipped in the pumpjack and beacons, the formula for 6 beacons can be shortened:
|2 + 2 * (6 * 0, 5 + 1) = 10 crude oil per second.
|4 + 2 * (6 * 0, 5) = 10 crude oil per second.
|}
|}



Revision as of 06:48, 1 February 2019

Pumpjack.png
Pumpjack

Pumpjack entity.png

Recipe

Time.png
5
+
Electronic circuit.png
5
+
Iron gear wheel.png
10
+
Pipe.png
10
+
Steel plate.png
5
Pumpjack.png
1

Total raw

Time.png
21.25
+
Copper plate.png
7.5
+
Iron plate.png
35
+
Steel plate.png
5

Recipe

Time.png
5
+
Electronic circuit.png
5
+
Iron gear wheel.png
10
+
Pipe.png
10
+
Steel plate.png
5
Pumpjack.png
1

Total raw

Time.png
27.5
+
Copper plate.png
20
+
Iron plate.png
70
+
Steel plate.png
5

Map color

Fluid storage volume

1000

Health

200

Stack size

20

Dimensions

3×3

Energy consumption

90 kW (electric)

Mining time

0.5

Mining speed

1

Mining area

1 tiles

Pollution

10/m

Module slots

2 slots

Prototype type

mining-drill

Internal name

pumpjack

Required technologies

Oil processing (research).png

Boosting technologies

Mining productivity (research).png

Produced by

Assembling machine 1.png
Assembling machine 2.png
Assembling machine 3.png
Player.png

Pumpjacks extract crude oil from oil fields. Each oil field can be covered by only one pumpjack at a fixed spot. The pumpjack will then output an amount of crude oil per cycle equal to 10 multiplied by the field's yield (e.g. 54 crude oil for 538% yield) per second. Without speed modules, one pumpjack cycle takes one second to complete.

Extracting oil lowers the field's yield by 1% per 300 pumpjack cycles to a minimum of 20% of the initial yield or 2 oil per second, whichever is larger. They are limited to a maximum output of 100 crude oil per cycle, achieved by an oil field with more than 999% yield. However, such a high yield is fairly rare with standard world generator settings.

Pumpjacks cannot be placed on a non-oilfield tile. Furthermore, the output pipe location is fixed relative to the pumpjack's orientation.

Tips

If oil fields are depleted (to the minimum of 20%) speed modules are a good option to raise the pumpjacks output. With two speed module 3's the output doubles from 2 to 4 crude oil per second and even more when using additional beacons, plus another 0.5 oil per beacon per second.

The formula to determine the modified output is:

Output of unmodified oil field * [1 + (number of modules in pumpjack * bonus from module) + (number of beacons * distribution efficiency * (number of modules in each beacon * bonus from module))].

Example
For 1 pumpjack on a depleted oil field with two level 3 speed modules and 6 beacons with each two level 3 speed modules: 2 * [1 + (2 * 0,5) + (6 * 0,5 * (2 * 0,5)) ] = 10 Crude oil per 1 second.
Assuming that there will be always two speed 3 modules equipped in the pumpjack and beacons, the formula for 6 beacons can be shortened: 4 + 2 * (6 * 0, 5) = 10 crude oil per second.

History

  • 0.15.0:
    • Pumpjacks can be turned on and off using the circuit network. They can also output the current oil mining rate.

See also