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Pumpjack: Difference between revisions

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{{Machinery
{{Machinery
|health      =100
|health      =100
|stackupto    =20
|stack_size  =20
|energy      =90 kW electric
|energy      =90 kW electric
|miningpower  =2
|miningpower  =2

Revision as of 20:15, 25 August 2016

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Pumpjacks extract crude oil from oil fields. Each oil field can be covered by only one pumpjack at a fixed spot. The pumpjack will then output an amount of crude oil per cycle equal to 1.0 multiplied by the field's yield (e.g. 5.4 crude oil for 538% yield) per second. Without speed modules one pumpjack cycle takes one second to complete.

Extracting oil lowers the field's yield by 1% per 75 pumpjack cycles to a minimum of 10%, or 0.1 oil units per sec.

Pumpjacks are limited to an maximum output of 10.0 crude oil per cycle, achieved by an oil field with more than 999% yield. However, such a high yield is fairly rare.

Pumpjacks output tile location is fixed relative to its orientation.

Pumpjacks cannot be placed on a non-oilfield tile.

Tips

If oil fields are depleted ( to the minimum of 10% ) speed Modules are a good option to raise the pumpjacks output. With two Speed module 3's the output doubles from 0.1 to 0.2 crude oil per second and even more when using additional Basic beacons ( + another 0.05 oil per beacon per second ).


The formula to determine the modified output is:

Output of unmodified oil field * ( Number of modules in pumpjack * bonus from module ) + output of unmodified oil field * ( number of Beacons * ( number of modules * distribution efficiency ) * bonus from module + 1 )

Example
For 1 pumpjack on a depleted oil field with two lvl 3 speed modules and 6 beacons with each two lvl 3 speed modules: 0,1 * ( 2 * 0,5 ) + 0,1 * ( 6 * ( 2 * 0,5 ) 0,5 + 1 ) = 0,5 Crude oil per 1 second.
Assuming that there will be always 2 modules equipped in pumpjack and beacons, formula can be shortened : 0,1 + 0,1 * ( 6 * 0,5 + 1 ) = 0,5 Crude oil per 1 second.


See also

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